factorise 5y^2 + 5y - 10
Answers
Answered by
0
Answer:
5y²-5y-10 = 5y²+5y-10y-10
= 5y(y+1)-1(y+1)
= (5y+1)(y+1)
hope this helps....
Answered by
1
Given:
A equation 5y²+5y-10
To find:
factor of the equation
Solution:
Given equation 5y²+5y-10
rewrite the equation
=5(y²+y-2)
=5(y²+2y-y-2)
=5{y(y+2)-1(y+2)}
=5(y-1)(y+2)
Hence, 5, y-1, y+2 are the factors of the equation 5y²+5y-10
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