Math, asked by gayathriy133, 1 year ago

Factorise ::: 6-×+×^2

sivaprasath: (x + [1+iroot23/2])(x - [1-iroot23/2])

Answers

Answered by Anonymous

Answer:

hope it's helpful......

Attachments:

sivaprasath: x^2 - 3x + 2x + 6 = x ( x - 3) + 2 ( x + 3) , not x ( x - 3) + 2 ( x - 3), okay ?

sivaprasath: ya,. I know,. I was trying to explain, where it gone wrong,. I agree your answer is CORRECT

sivaprasath: (=> abhi , bro your's is correct)

sivaprasath: :)

Anonymous: ok

Anonymous: sorry

Anonymous: n thanks

Answered by Anonymous

Answer:

by use this formula:---------

x=[-b±root of (b^2-4ac)]/2a.

so ...

x=[-(-1)±root of {(-1)^2-4*1*6)}]/2

=[1±root of {(1-24)}]/2

=[1±root of (-23)}]/2.

Step-by-step explanation:

here take +ve and -ve sign .....

and find the value of x..

I hope this is right and helpful for u.

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