Question

factorise 6 a b minus b square + 12 AC - 2 BC​

Answer 1

Explanation:

$6ab - {b}^{2} + 12ac - 2bc = >$

$b(6a - b) + 2c(6a - b) = >$

$(b + 2c)(6a - b)$

Hope it helps you.

Answer 2

Answer:

6ab-bsquare +12ac-2bc

=b(6a-b)+2c(6a-b)

=(b+2c) (6a-b)

Explanation:

we have to take tge common factor.

that is,b and 2c