Question

factorise 6(x+2y)^3 +8(x+2y,)^2​

Answer 1

Step-by-step explanation:

it can't solve more than this

see attachment

Answer 2

Given:

$6(x+2y)^3+8(x+2y)^2$

To find:

Factorize the given expression

Solution:

$6(x+2y)^3+8(x+2y)^2$

$2\times (x+2y)(x+2y)(x+2y)+2\times 2\times 2(x+2y)(x+2y)$

Taking $2(x+2y)^2$ common then, we get

$2(x+2y)^2(3(x+2y)+4)$

$2(x+2y)^2(3x+6y+4)$

$2(x+2y)^2(3x+6y+4)$

Hence, the expression factorize as

$2(x+2y)^2(3x+6y+4)$