Question

factorise 6(x-y)^2-x+y-15​

Answer 1

GIVEN :

The expression is $6(x-y)^2-x+y-15$ and factorise it.

TO FACTORISE :

The given expression is  $6(x-y)^2-x+y-15$

SOLUTION :

Given that the expression is $6(x-y)^2-x+y-15$

First factorising the given expression we have that,

That is now solving the given expression  as below:

$6(x-y)^2-x+y-15$

By using the algebraic identity :

$(a-b)^2=a^2-2ab+b^2$

$=6(x^2-2xy+y^2)-x+y-15$

By using the Distributive property :

a(x+y+z)=ax+ay+az

$=6(x^2)+6(-2xy)+6(y^2)-x+y-15$

$=6x^2-12xy+ 6y2-x + y - 15$

$=6x(x-2y)-(x+15)+y(6y+1)$

∴ $6(x-y)^2-x+y-15=6x(x-2y)-(x+15)+y(6y+1)$

∴ These groups have no common factor.

Answer 2

Answer:

6(x-y)^2-x+y-15

=6(x-y)^2-(x-y)-15

=6(x-y)^2-10(x-y)+9(x-y)-15

[ (x-y)=a]

=6a^2-10a+9a-15

=2a(3a-5)+3(3a-5)

=(2a+3)(3a-5)

=(2x-2y+3)(3x-3y-5)

Step-by-step explanation: