FACTORISE:- 63a^2b^2 -7
pls solve it's urgent
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Answered by
84
Heya !!!
this is your answer.....
Given :---
63a²b² - 7
Taking Out Common .....
7 (9a²b² - 1) = 0
7 {(3ab)² - (1)} = 0.
7 {(3ab -1)(3ab+1)} = 0. .....{a² -b² = (a-b)(a+b)}.....
7 (3ab -1) (3ab +1) = 0.
HOPE IT HELPS
this is your answer.....
Given :---
63a²b² - 7
Taking Out Common .....
7 (9a²b² - 1) = 0
7 {(3ab)² - (1)} = 0.
7 {(3ab -1)(3ab+1)} = 0. .....{a² -b² = (a-b)(a+b)}.....
7 (3ab -1) (3ab +1) = 0.
HOPE IT HELPS
RehanAhmadXLX:
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happy:-)
who says it is equal to zero??
Yeahh
Why is = 0 given.I didn't understand.
Answered by
27
Answer:7(3ab -1)(3ab +1)
Step-by-step explanation:
Given 63a^2 -7
Take out common
= 7 (9 a^2 b^2 - 1)
By (a ^2- b^2 )= a^2 - b^2
= 7( (3ab)^2 - (1)^2)
=7 (3ab -1) (3ab +1)
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