Question

FACTORISE :63a2 -112B 2

Answer 1

First of all there is no square root of 63 and 112 so, we must take the common numbers..
i.e. ( 3 * 3 * 7 * a * a ) - ( 2 * 2 * 2 * 2 * 7 * b * b )
Taking the common factors we'll get 7 ( 9 a^2 - 16 b^2 )
= 7 ( 3a^2 - 4b^2 )
And your final answer will be 7 ( 3a - 4b ) ( 3a + 4b )
Hope it helped...

Answer 2

Answer:

7[3a-4b][3a+4b]

Step-by-step explanation:

63 is divisible in 7 table

So we can also try dividing it in 7 table

=16

According to the formulae :a^2-b^2=[a+b][a-b]

square of 16 and 9 is [4]^2,[3]^2

7{[3a^2]-[4b^2]}

7[3a-4b][3a+4b]