factorise 63a²-112b²
Answers
Answered by
144
63a² – 112b²
= 7( 9a2 -16b2)
=7[ (3a)2 –(4b)2]
So from third identity, it can be written as
=7(3a-4b)( 3a+4b)
= 7( 9a2 -16b2)
=7[ (3a)2 –(4b)2]
So from third identity, it can be written as
=7(3a-4b)( 3a+4b)
Answered by
55
Answer:
Step-by-step explanation:
63a²-112b²
7[9a²-16b²]
7[(3a)²-(4b)²]
7[(3a+4b)(3a-4b)]
Factorized
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