Question

factorise 64\125xcube -8-96xsquare\25+48x\5​

Answer 1

Answer:

Both  

125x3=(5x)3and64=43 are perfect cubes,

so this is a natural case for the sum of cubes identity: (a3+b3

=(a+b)(a2−ab+b2)

Witha

=5xand

=4

we find:125x3+64

=(5x)3+43

=(5x+4)((5x)2−(5x)(4)+42)

=(5x+4)(x2−20x+16)

Step-by-step explanation.