factorise:-64γ2−64lp+4p
Answers
Answer:
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Step-by-step explanation:
STEP
1
:
Equation at the end of step 1
p - 26p4
STEP
2
:
STEP
3
:
Pulling out like terms
3.1 Pull out like factors :
p - 64p4 = -p • (64p3 - 1)
Trying to factor as a Difference of Cubes:
3.2 Factoring: 64p3 - 1
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0-b3 =
a3-b3
Check : 64 is the cube of 4
Check : 1 is the cube of 1
Check : p3 is the cube of p1
Factorization is :
(4p - 1) • (16p2 + 4p + 1)
Trying to factor by splitting the middle term
3.3 Factoring 16p2 + 4p + 1
The first term is, 16p2 its coefficient is 16 .
The middle term is, +4p its coefficient is 4 .
The last term, "the constant", is +1
Step-1 : Multiply the coefficient of the first term by the constant 16 • 1 = 16
Step-2 : Find two factors of 16 whose sum equals the coefficient of the middle term, which is 4 .
-16 + -1 = -17
-8 + -2 = -10
-4 + -4 = -8
-2 + -8 = -10
-1 + -16 = -17
1 + 16 = 17
2 + 8 = 10
4 + 4 = 8
8 + 2 = 10
16 + 1 = 17
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
-p • (4p - 1) • (16p2 + 4p + 1)