Question

factorise {(64÷27)z^3 - 1^3 } + (16÷3)z^2 +4z​

Answer 1

Answer:

64/27z3-1-16/3z2+4z

Ans Final result :

(4z - 3)3

—————————

27

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "z2" was replaced by "z^2". 1 more similar replacement(s).

Step by step solution :

Step 1 :

16

Simplify ——

3

Equation at the end of step 1 :

64 16

(((——•(z3))-1)-(——•z2))+4z

27 3

Step 2 :

Equation at the end of step 2 :

64 16z2

(((——•(z3))-1)-————)+4z

27 3

Step 3 :

64

Simplify ——

27

Equation at the end of step 3 :

64 16z2

(((—— • z3) - 1) - ————) + 4z

27 3

Step 4 :

Equation at the end of step 4 :

64z3 16z2

((———— - 1) - ————) + 4z

27 3

Step 5 :

Rewriting the whole as an Equivalent Fraction :

5.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 27 as the denominator :

1 1 • 27

1 = — = ——————

1 27

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

5.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

64z3 - (27) 64z3 - 27

——————————— = —————————

27 27

Equation at the end of step 5 :

(64z3 - 27) 16z2

(——————————— - ————) + 4z

27 3

Answer 2

Answer:

(4 /3 z - 1 ) ^3

Step-by-step explanation:

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