Math, asked by joelmk12345, 10 months ago

factorise 64-(a+1)²​

Answers

Answered by aayusharora045
2

Answer:

Step-by-step explanation:

64-(a+1)^2=0

64-(a^2+2a+1)=0

64-a^2-2a-1=0

-a^2-2a+63=0

a^2+2a-63=0

a^2-9a+7a-63=0

a(a-9)+7(a-9)=0

(a+7)(a-9)=0

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Answered by adarshhbro
0

Step-by-step explanation:

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