Factorise 64 a^2+96ab+36b^2
allanpaulsojan9:
By splitting the middle term
Answers
Answered by
93
Factorise the following
64a² + 96ab + 36b²
breaking with the identity ( a + b )²
(8a)² + 2 × 8a × 6b + (6b)²
(8a + 6b)².
(8a +6b)(8a+6b)
If you find my answer helpful please mark it as a brainliest..
this is your answer...
64a² + 96ab + 36b²
breaking with the identity ( a + b )²
(8a)² + 2 × 8a × 6b + (6b)²
(8a + 6b)².
(8a +6b)(8a+6b)
If you find my answer helpful please mark it as a brainliest..
this is your answer...
Answered by
26
64a² + 96ab + 36b²
use this identity
(a + b)² = a² + 2ab + b²
now
=> (8a)² + 2.8a.6b + (6b)² = ( 8a + 6b)²
=> (8a+6b) (8a+6b)
is the factor .
———————————————
Hope it will help you ...✌✌
use this identity
(a + b)² = a² + 2ab + b²
now
=> (8a)² + 2.8a.6b + (6b)² = ( 8a + 6b)²
=> (8a+6b) (8a+6b)
is the factor .
———————————————
Hope it will help you ...✌✌
Similar questions