Question

factorise 64 a^2b-144b^3

Answer 1

64^2

(a+b)^2=a^2+2ab+b^2

Answer 2

Solution

$64 a{}^{2}b - 144b {}^{3} \\ = b(64a {}^{2} - 144b {}^{2} ) \\ = b((8a) {}^{2} - (12b) {}^{2} ) \\ = b(8a - 12b)(8a + 12b) \\ = b \times 4 \times 4(2a - 3b)(2a + 3b)$