Question

Factorise :
64(a+b)^2- 81(a-b)^2

Answer 1

64(a + b)² = (8)²(a + b)²

=> 64(a + b)² = [ 8(a + b)]²

Similarly,

81(a - b)² = [ 9(a - b)]²

So,

64(a + b)² - 81(a - b)²

= [8(a + b)]² - [ 9(a - b)]²

=> (8a + 8b)² - (9a - 9b)²

Now, using the identity,

a² - b² = (a + b)(a - b), we can solve.

=> (8a + 8b)² - (9a - 9b)²

=> [8a + 8b - (9a - 9b)](8a + 8b + 9a - 9b)

=> (8a + 8b - 9a + 9b)(17a - b)

=> (17b - a)(17a - b)


Your answer :- (17b - a)(17a - b)


Hope it helps dear friend ☺️

Answer 2

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The answer of u r question is..✌️✌️

Is in the pic.

Thank you..⭐️⭐️⭐️