Question

Factorise : 64 - a cube b cube + 8 - 2ab

Answer 1

Answer:

$(4 - ab)(17 + {a}^{2} {b}^{2} + 4ab)$

Step-by-step explanation:

$formula \\ \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + {y}^{2} +xy) \\ \\ 64 - {a}^{3} {b}^{3} + 8 - 2ab \\ \\ {4}^{3} - {( ab)}^{3} + 2(4 - ab) \\ \\ (4 - ab)(16 + {a}^{2} {b}^{2} + 4ab) + 2(4 - ab) \\ \\ (4 - ab)(17 + {a}^{2} {b}^{2} + 4ab)$

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Answer 2

Step-by-step explanation:

$\begin{lgathered}formula \\ \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + {y}^{2} +xy) \\ \\ 64 - {a}^{3} {b}^{3} + 8 - 2ab \\ \\ {4}^{3} - {( ab)}^{3} + 2(4 - ab) \\ \\ (4 - ab)(16 + {a}^{2} {b}^{2} + 4ab) + 2(4 - ab) \\ \\ (4 - ab)(17 + {a}^{2} {b}^{2} + 4ab) \\ \\\end{lgathered}$