Factorise 64 a3-125 b3 by using Identity.
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64a³-125b³
(4a)³-(5b)³
We know that,x³-y³=(x-y)(x²+xy+y²)
(4a-5b)[(4a)²+4a×5b+(5b)²]
(4a-5b)(16a²+20ab+25b²)
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