factorise 64 a3 -27 b3 -144a2b + 108 ab2
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Answer:
64a³-27b³-144a²b+108ab².
(4a)³-(3b)³-3(4a)(3b)(4a-3b).
It is in the form of a³-b³-3ab(a-b)=(a-b)³.
(4a)³-(3b)³-3(4a)(3b)(4a-3b)=(4a-3b)³.
I think this is your answer.
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