Question

factorise 64 a3 -27 b3 -144a2b + 108 ab2 ​

Answer 1

Answer:

64a³-27b³-144a²b+108ab².

(4a)³-(3b)³-3(4a)(3b)(4a-3b).

It is in the form of a³-b³-3ab(a-b)=(a-b)³.

(4a)³-(3b)³-3(4a)(3b)(4a-3b)=(4a-3b)³.

I think this is your answer.