Question

Factorise (64 p³ + 125³ )​

Answer 1

Step-by-step explanation:

Rewrite

64

x

3

as

(

4

x

)

3

.

(

4

x

)

3

−

125

Rewrite

125

as

5

3

.

(

4

x

)

3

−

5

3

Since both terms are perfect cubes, factor using the difference of cubes formula,

a

3

−

b

3

=

(

a

−

b

)

(

a

2

+

a

b

+

b

2

)

where

a

=

4

x

and

b

=

5

.

(

4

x

−

5

)

(

(

4

x

)

2

+

4

x

⋅

5

+

5

2

)

Answer 2

Answer:

(4p+5)(16p^2-20p+25)

Step-by-step explanation:

(64p^3 + 125)

= (4p)^3 + 5^3

= (4p + 5)(16p^2-20p+25)