factorise 64a^3-144a^2b+108ab^2-27b^3
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64a³ - 27b³ - 144a²b + 108ab²
Here, using the identity -
(a - b)³ = a³ - b³ - 3a²b + 3ab²
⇒ 64a³ - 27b³ - 144a²b + 108ab² = (4a)³ - (3b)³ - 3(4a)²*(3b) + 3(4a)*(3b)²
⇒ (4a - 3b)³
⇒ (4a - 3b)*(4a - 3b)*(4a - 3b)
Answer
Read more on Brainly.in - https://brainly.in/question/1222927#readmore
Here, using the identity -
(a - b)³ = a³ - b³ - 3a²b + 3ab²
⇒ 64a³ - 27b³ - 144a²b + 108ab² = (4a)³ - (3b)³ - 3(4a)²*(3b) + 3(4a)*(3b)²
⇒ (4a - 3b)³
⇒ (4a - 3b)*(4a - 3b)*(4a - 3b)
Answer
Read more on Brainly.in - https://brainly.in/question/1222927#readmore
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