Question

factorise .... 64a^3 -27b^3 -144a^2b + 108 ab^2

Answer 1

$we \: know \: that \\ {(a - b)}^{3} = {a}^{3} - {b}^{3} - 3{a}^{2} b + 3a {b}^{2} \\ so {(4a - 3b)}^{3} = {64a}^{3} - {27b}^{3} - 144 {a}^{2} b + 108a {b}^{2} \\ {(4a - 3b)}^{3} \\ \\ i \: hope \: it \: help \: u \: \\ mark \: as \: brainlist \: answer$