Math, asked by kannanchellappan2012, 11 months ago

factorise 64a^3-27b^3-144a^2b+108ab^2​

Answers

Answered by vatsaman
1

Answer:

(4a-3b)^3

Step-by-step explanation: (A-B)^3=A^3-B^3-3A^2B-3AB^2

4^3=64

3^3=27

3*4^2*3=144

3*4*3^2=108

Answered by Anonymous
6

Hey user!

Here to help you..

Answer:

⇒(4a - 3b)(4a - 3b)(4a - 3b)

Step-by-step explanation:

⇒ 64a^3 - 27b^3 -144a²b + 108ab²

⇒ (4a)^3 - (3b)^3 - 3(4a)²(3b) + 3(4a)(3b)²

⇒ (4a - 3b)^3

⇒(4a - 3b)(4a - 3b)(4a - 3b)

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