factorise 64a^3-343 solve it guys!!!
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Hey QueenShwetha!
64a^3 - 343
(4a)^3 - 7^3
It is in the form a^3 - b^3=(a-b) (a^2+ab+b^2)
so, a=4a b=7
(4a - 7) [ ( 4a)^2 = 4a*7 + 7^2]
ans = (4a - 7) ( 16x^2 = 28a =49)
Hope it is helpful!!
:)
64a^3 - 343
(4a)^3 - 7^3
It is in the form a^3 - b^3=(a-b) (a^2+ab+b^2)
so, a=4a b=7
(4a - 7) [ ( 4a)^2 = 4a*7 + 7^2]
ans = (4a - 7) ( 16x^2 = 28a =49)
Hope it is helpful!!
:)
PoorViTae:
It's 16 a^ 2
sryyy
And it's not = it's + .......................again sryyy
it's okk
no problem
:)....I'm not used to typing
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