Question

factorise 64a^3-343 solve it guys!!!

Answer 1

$64 {a}^{3} - 343 \\ = {(4a)}^{3} - {7}^{3} \\ = (4a - 7)(16 {a}^{2} + 49 + 28a)$

Answer 2

Hey QueenShwetha!

64a^3 - 343
(4a)^3 - 7^3
It is in the form a^3 - b^3=(a-b) (a^2+ab+b^2)
so, a=4a b=7
(4a - 7) [ ( 4a)^2 = 4a*7 + 7^2]

ans = (4a - 7) ( 16x^2 = 28a =49)

Hope it is helpful!!
:)