Question

Factorise
64a^6-b^6.​

Answer 1

Step-by-step explanation:

(2a)⁶ - b⁶

{(2a)³}² - (b³)²

using property a²-b²= (a+b)(a-b)

{(2a)³+b³} {(2a)³-b³}

using property (a³+b³) = (a+b)(a²-ab+b²)

(a³-b³) = (a-b)(a²+ab+b²)

(2a+b)(4a²-2ab+b²)(2a-b)(4a²+2ab+b²)