Question

factorise 64a+a^4 plz hel me solving this question​

Answer 1

Answer:

 As we will factorize this equation as taking a common factor a

Step-by-step explanation:

hence ,

             >>> a(a^3+64)=0,  

             >>> a ( a^3+ {4}^3)

 using formula

                     (a^3+b^3)=(a+b)(a^2-ab+b^2)

           

           >>>  a(`a^3+{4}^3)=a [(a+b)(a^2-4a+{4}^2)]

            >>  a [(a+4)(a^2-4a+{4}^2)]=0                

        taking roots from the equation

            a=0          , (a+4)=0    

we got two values of a=0,-4

I hope it helps...

Answer 2

Answer:

a (4-a) (16+4a+a²)

Step-by-step explanation:

64a+a^4 = a (64 - a³)

              = a {(4)³ - (a)³}

              = a (4-a) (4²+4a+a²)

              = a (4-a) (16+4a+a²)