Question

factorise 64a saqure +96ab + 36 b saqure

Answer 1

Factorise the following

64a² + 96ab + 36b²

breaking with the identity ( a + b )²

(8a)² + 2 × 8a × 6b + (6b)²

(8a + 6b)².

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Answer 2

The factorisation of $64a^2+96ab+36b^2$ is $(8a+6b)(8a+6b)$.

Step-by-step explanation:

We have,

$64a^2+96ab+36b^2$

To find, the factorisation of $64a^2+96ab+36b^2=?$

∴ $64a^2+96ab+36b^2$

$=(8a)^2+2(8a)(6b)+(6b)^{2}$

$=(8a+6b)^{2}$

[ ∵ $(a+b)^{2}=a^{2}+2ab+b^{2}$]

$=(8a+6b)(8a+6b)$

Hence, the factorisation of $64a^2+96ab+36b^2$ is ($(8a+6b)(8a+6b)$.