Question

Factorise: –64a³ –12a + 48a²

Answer 1

Question:

64a³-12a+48a²

Step by step explanation:

(4a)³-3(1)²(4a)+3(1)(4a)²

suitable identities is x³-y³-y³-3x²y=(x-y)³

(1)³-(4a)³-3(1)²(4a)+3(1)(4a)²

=(1-4a)³

Answer:(1-4a)³

Hope it's helpful

Answer 2

Step-by-step explanation:

-a(64a²-48a+12)

12 =16-4=4²-2²

-a((8a)²-2*8a*4+4² -4)

-a((8a-4)²-2²)

a²-2ab+b²=(a+b)², a=8a , b=4

a²-b²=(a+b)(a-b), a=8a-4, b=2

-a(8a-4+2)(8a-4-2)

=-a(8a-2)(8a-6)

=-a×2(4a-1)×2(4a -3)

=-4a(4a-1)(4a-3)