Question

Factorise 64a³ - 27b³ - 144a²b + 108 ab²​

Answer 1

Step-by-step explanation:

We have, 64a 3 −27b 3 −144a 2 b+108ab 2 =(4a) 3 +(−3b) 3 −36ab(4a−3b)

Using, (a+b)

3 =a 3 +b 3 +3ab(a+b)

=(4a) 3 +(−3b) 3 +3(4a)(−3b)(4a−3b)

=(4a−3b)3

=(4a−3b)(4a−3b)(4a−3b)

@By Samu___❤___

Answer 2

${4a}^{3} - {3b}^{3} - 3 \times {4a}^{2} \times 3b + 3 \times 4 a\times {3b}^{2}$

${4a - 3b}^{3}$

(4a-3b)(4a-3b)(4a-3b)