Question

factorise
64a³-27b³-144a²b+108ab²​

Answer 1

SOLUTION

formula

$(a + b) {}^{3} = {a}^{3} - {b}^{3} - 3a {}^{2} b + 3ab {}^{2}$

=) 64a^3 -27b^3- 144a^2b +108ab^2

=) (4a-3b)^3

HOPE it helps ✔️

Answer 2

Answer:−

›»› The expression = (4a - 3b)³

$\Large{\bold{\blue{\underline{\red{gi}\:\pink{ve}\green{n}\purple{:-}}}}}$

64a³ - 27b³ - 144a²b + 108ab²

$\Large{\bold{\blue{\underline{\red{To}\:\pink{Fin}\green{d}\purple{:-}}}}}$

Factorize the expression.

$\Large{\bold{\pink{\underline{\red{So}\purple{lut}\green{ion}\orange{:-}}}}}$

Let's start solving the factorization and understand the steps to get our final result.

⇛ 64a³ - 27b³ - 144a²b + 108ab²

Short the polynomial expression in descending order,

⇛ 64³ - 144a²b + 108ab² - 27b³

Do factorization,

⇛ (4a - 3b)³

Hence Solved !

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✒ Factozisation :

Factorizing is to make a single term: try to write everything as products (multiplication), for example:

→ 6x² - 9x + 10 = (2x - 5) (3x - 2)

Step ① :

Find a common factor

Example:

→ 4xy + x⁴ + x = x(4x + x³ + 1)

Step ② :

Count the number of terms

(terms are separated by + or −)

If none of these methods work, re-arrange the terms, or remove brackets and start again.