Math, asked by saniyakhan1337, 5 months ago

factorise 64a3-27b3

Answers

Answered by Msaikrishna2005

0

Answer:

(4a)³-(3b)³

= (4a-3b)(16a²+12ab+9b²)

Answered by harshitusn18

0

Answer:

(4a-3b)(16a²+12ab+9b²)

Step-by-step explanation:

By formula x³-y³=(x-y)(x²+xy+y²)

64a³-27b³= (4a)³-(3b)³

=(4a-3b)[(4a)²+4a*3b+(3b)²]

=(4a-3b)(16a²+12ab+9b²)

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