Question

factorise 64a³+8b³+96a²b+48ab²​

Answer 1

Step-by-step explanation:

Factor from 8

$8(8 {a}^{3} + {b}^{3} + 12 {a}^{2}b + 6 {ab}^{2})$

$8((2a + b)(4 {a}^{2} - 2ab + {b}^{2} + 6ab(2a + b))$

$8((2a + b)(4 {a}^{2} - 2ab + {b}^{2} + 6ab))$

$8((2a + b)(4 {a}^{2} + 4ab + {b}^{2} ))$

$8((2a + b)(2a + b)^{2} )$

$8(2a + b)^{3}$