Question

Factorise 64a³–b³. Solve it.​

Answer 1

Step-by-step explanation:

64a³–b³.

= (4a)^3 -(b)^3

= (4a-b)(16a^2 + b^2 + 4ab)

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Answer 2

Answer:

Hello mate❤️❤️

${64a}^{3} - {b}^{3}$

$= {(4a)}^{3} - {b}^{3}$

$=(4a - b)(16 {a}^{2} + 4ab + {b}^{2} )$

Hope this help you