Question

factorise 64a⁶ - b⁶​

Answer 1

THIS IS THE ANSWER

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Answer 2

Answer:

Answer:

64a^6 - 729b^6

a⁶-b⁶ = (a²)³-(b²)³

a⁶ =64a⁶      b⁶ = 729b⁶

a =  2a          b=3b

a⁶-b⁶=(a²-b²)(a⁴+a²b²+b⁴)

64a⁶-729b⁶= (4a²-9b²)(16a⁴+36a²b²+81b⁴)

                   =(2a+3b)(2a-3b)(16a⁴+36a²b²+81b⁴)

                 

Step-by-step explanation:

a³-b³=(a-b)(a²+ab+b²)

a⁶-b⁶=(a²-b²)(a⁴+a²b²+b⁴)

a²-b²=(a+b)(a-b)

Step-by-step explanation:

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