Question

factorise 64acube+27

Answer 1

Here is your answer

$(4a) {}^{3} + 3 {}^{3} \\ = (4a + 3)((4a) {}^{2} + 3 {}^{2} - 4a \times 3) \\ = (4a + 3)(16a {}^{2} + 9 - 12a)$
Hope it helps you