Factorise 64mcube -343ncube with identity
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- Answer: Step-by-step explanation: 64m∧3 – 343n∧3 = (4m)∧3 – (7n)∧3 a³–b³= (a–b) (a²+ab+b²) (4m)³–(7n)³=(4m–7n) [(4m)²+(4m*7n)+(7n)²] =(4m–7n)(16m²+28mn+49n²)
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Solution:
Given ,
64m^3 - 343n^3
Identity
【m^3 - n^3 =( m - n )(m^2 + mn + n^2 】
substituting values,
(4m - 7n)(16m^2 + 28mn + 49n^2)
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