Factorise : 64p^6 – q^6.
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Answer:
=p^6(64-1)
Step-by-step explanation:
i hope it's helpful to you
Answered by
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Answer:
64p^6-q^6.
((4p³))³-((q³))³.
It is in the form of a³-b³=(a-b)(a²+b²+ab).
Where a=(4p)³ & b=(q)³.
((4p)³)³-((q)³)³=((4p)³-(q)³)((4p³)²+((q)³)²+((4p)³)((q)³).
=(4p³-q³)(4p^6+q^6+4p³q³).
=4p³(4p^6+q^6+4p³q³)-q³(4p^6+q^6+4p³q³).
=16p^9+4p³q^6+16p^6q³-4p^6q³-q^9-4p³q^6.
=16p^9+16p^6q³-4p^6q³-q^9.
I think this is your answer.
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