Question

factorise 64x^2 +16x+1​

Answer 1

Answer:

нσℓα мαтє ❤️!!

64x²+16x+1

=)64x²+8x+8x+1

=)8x(8x+1)+1(8x+1)

=)(8x+1)(8x+1).

ⓗⓞⓟⓔ ⓘⓣ ⓗⓔⓛⓟⓢ ⓨⓞⓤ ☺!! ❤️

Answer 2

$\large \underline{ \underline{ \sf \: Answer : \: \: \: }}$

$\to \sf x = - \frac{1}{8}$

$\large \underline{ \underline{ \sf \: Explaination : \: \: \: }}$

By prime factorisation method ,

$\to \sf {64x}^{2} + 16x + 1 = 0 \\ \\ \to \sf {64x}^{2} + 8x + 8x + 1 = 0 \\ \\ \to \sf 8x(8x + 1) + 1(8x + 1) = 0 \\ \\ \to \sf (8x + 1)(8x + 1) =0 \\ \\ \to \sf x = - \frac{1}{8}$

Hence , the required value of x is -1/8