Math, asked by unique9978, 12 hours ago

factorise 64x^2 + 16y^2 - 64xy​

Answers

Answered by spondita24
0

Answer:

(8x-4y)^2

Step-by-step explanation:

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Answered by krishnapriyasuresh13
1

Answer:

Use the sum-product pattern

2

+

8

+

1

6

x^{2}+{\color{#c92786}{8x}}+16

x2+8x+16

2

+

4

+

4

+

1

6

x^{2}+{\color{#c92786}{4x}}+{\color{#c92786}{4x}}+16

x2+4x+4x+16

2

Common factor from the two pairs

2

+

4

+

4

+

1

6

x^{2}+4x+4x+16

x2+4x+4x+16

(

+

4

)

+

4

(

+

4

)

x(x+4)+4(x+4)

x(x+4)+4(x+4)

3

Rewrite in factored form

(

+

4

)

+

4

(

+

4

)

x(x+4)+4(x+4)

x(x+4)+4(x+4)

(

+

4

)

(

+

4

)

(x+4)(x+4)

(x+4)(x+4)

4

Combine to a square

(

+

4

)

(

+

4

)

(x+4)(x+4)

(x+4)(x+4)

(

+

4

)

2

\left(x+4\right)^{2}

(x+4)2

Solution

(

+

4

)

2

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