Question

factorise 64x^2y^2-81z^2​

Answer 1

Step-by-step explanation:

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Factor 64x^2-81y^2

64x2−81y264x2-81y2

Rewrite 64x264x2 as (8x)2(8x)2.

(8x)2−81y2(8x)2-81y2

Rewrite 81y281y2 as (9y)2(9y)2.

(8x)2−(9y)2(8x)2-(9y)2

Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b)a2-b2=(a+b)(a-b) where a=8xa=8x and b=9yb=9y.

(8x+9y)(8x−(9y))(8x+9y)(8x-(9y))

Multiply 99 by −1-1.

(8x+9y)(8x−9y)(8x+9y)(8x-9y)

Answer 2

Answer:

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