Question

factorise 64x^3+125y^3+240x^2y+300xy^2​

Answer 1

$factorise = \\ 64x^3+125y^3+240x^2y+300xy^2 \\ \\ solution. \\ \\ 64x^3+125y^3+240x^2y+300xy^2 \\ \\ = 64 {x}^{3} + 160 {x}^{2} y + 100x {y}^{2} + 80 {x}^{2} y \\ + 200x {y}^{2} + 125 {y}^{3} \\ \\ = 4x(16 {x}^{2} + 40xy + 25 {y}^{2} ) \\ + 5y(16 {x}^{2} + 40xy + 25 {y}^{2} ) \\ \\ = (4x + 5y)(16 {x}^{2} + 40xy + 25 {y}^{2}) \\ \\ =( 4x + 5y)(4 {x} + 5y)^{2} \\ \\ = (4x + 5y)^{3} \: \: is \: the \: answer.. \\ hope \: it \: help \: you \:$

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