Question

Factorise 64x^3 +125y^3 - 64z^3 + 240 xyz

Answer 1

Answer:

Factorise with (a^3+b^3++c^3-3abc) formula

Explanation:

64x^3 + 125y^3 -64z^3+240xyz

=(4x)^3+(5y)^3+(-4z)^3 - 3(4x)(5y)(-4z)

=(4x+5y-4z)^3

[since, (a)^3+(b)^3+(c)^3 - 3abc =

(a+b+c)^3]

Hope it helps.

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Answer 2

Answer:

it is write

Explanation:

Explanation:

64x^3 + 125y^3 -64z^3+240xyz

=(4x)^3+(5y)^3+(-4z)^3 - 3(4x)(5y)(-4z)

=(4x+5y-4z)^3

[since, (a)^3+(b)^3+(c)^3 - 3abc =

(a+b+c)^3]

Hope it helps.

Please mark it as Brainliest.