Question

Factorise 64x^3 – 343y^3 using suitable identity.

Answer 1

Answer:

The answer is $(4x-7y)(16x^2+28xy+49y^2)$

Step-by-step explanation:

   $64x^3-343y^3$

$=(4x)^3-(7y)^3$, write in the form of $a^3-b^3$

$=(4x-7y)[(4x)^2+(4x)(7y)+(7y)^2]$, using $a^3-b^3=(a-b)(a^2+ab+b^2)$

$=(4x-7y)(16x^2+28xy+49y^2)$, simplify