Question

Factorise 64x^3+729x^3

Answer 1

a³ + b³ = (a +b)(a² -ab + b²)

64x³ + 729x³ = (4x)³ + (9x)³

Now you can use the above identity to get your answer...

Answer 2

The factorisation of $64x^3+729y^3$ is $(4x+9y)(16x^2-36xy+81y^2)$.

Step-by-step explanation:

We have,

$64x^3+729y^3$

To find, the factorisation of $64x^3+729y^3=?$

∴ $64x^3+729y^3$

$=(4x)^3+(9y)^3$

Using the algebraic identity,

$a^3+b^3=(a+b)(a^2-ab+b^2)$

$=(4x+9y)[(4x)^2-(4x)(9y)+(9y)^2]$

$=(4x+9y)(16x^2-36xy+81y^2)$

The factorisation of $64x^3+729y^3=(4x+9y)(16x^2-36xy+81y^2)$

Hence, the factorisation of $64x^3+729y^3$ is $(4x+9y)(16x^2-36xy+81y^2)$.