Question

factorise 64x square- y square​

Answer 1

Answer:

(8x+y) ( 8x-y)

Step-by-step explanation:

64x ^2 - y ^2

rewrite 64x^2 as (8x)^2

(8x)^2 -y^2

since , both terms are perfect square ,factors using the differenceof square formula

a^2-b^2 = (a-b)(a+b)

where a =8x and b = y

(8x+y) (8x-y)

Answer 2

★GIVEN:-

$\implies \: (64x {}^{2} - y {}^{2} )$

★find:-

given quantity factorise

★solution:-

$\implies \: 64x {}^{2} - y {}^{2}$

can we be written as

$\implies \: ( 8x) {}^{2} - y {}^{2}$

we know that formula of

$\implies \pink{ {a}^{2} - b {}^{2} = (a + b)(a - b) }$

$\implies \:( 8x + y)(8x - y)$

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I hope it helps you