Question

Factorise 64x3 144 x2 27 using identity.​

Answer 1

Answer:

64a3 – 27b3 – 144a2b + 108ab2 = (4a)3 – (3b )3 – 3(4a)2(3b) + 3(4a)(3b)2. = (4a – 3b)3. = (4 a – 3b)(4a – 3b)(4a – 3b). Concept: Algebraic ...