Factorise 64x³+y³-z³+12xyz
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Hi
★ Thanks ★
We need to use this formula :
a³ + b³ + c³ - 3abc = ( a + b + c ) ( a² + b² + c² - ab - bc - ca )
====================
now
64x³ + y³ - z³ + 14xyz
= ( 4x )³ + y³ + ( - z )³ - 3 . 4x . y . ( -z )
= ( 4x + y - z ) ( 16x² + y² + z² - 4xy + yz + 4xz )
====================================
★ Thanks ★
We need to use this formula :
a³ + b³ + c³ - 3abc = ( a + b + c ) ( a² + b² + c² - ab - bc - ca )
====================
now
64x³ + y³ - z³ + 14xyz
= ( 4x )³ + y³ + ( - z )³ - 3 . 4x . y . ( -z )
= ( 4x + y - z ) ( 16x² + y² + z² - 4xy + yz + 4xz )
====================================
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