Question

factorise 64y^3 +8/27​

Answer 1

Answer:

$(4y+\frac{2}{3})(16y^{2}-\frac{8y}{3}+\frac{4}{9})$

Step-by-Step Explanation

$64y^3+\frac{8}{27} \\=(4y)^3+(\sqrt[3]{\frac{8}{27} }^3)\\\\=(4y+\frac{2}{3})(4^2y^2-\frac{2}{3}*4y+(\frac{2}{3})^2)\\\\=(4y+\frac{2}{3})(16y^2-\frac{8y}{3}+\frac{4}{9})$

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