Math, asked by avardhan047, 7 months ago

Factorise 64z3+343y3.

Answers

Answered by AarchiChhabria
1

Answer:

64z³+343y³

(4z)³+(7y)³

 {a}^{3} +  {b}^{3}  = (a + b)( {a}^{2}-ab + {b}^{2}  )

here a=4z and b=7y

(4z+3y)[(4z)²-4z×3y+(3y)²]

(4z+3y)(16z²-12yz+9y²)

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