Question

Factorise : 6a^2 - 3a^2b - bc^2 + 2c^2​​​​​​​

Answer 1

6a^2 - 3a^2b - bc^2 + 2c^2

3a^2(2-a)+ c^2(2-b)

(3a^2+c^2) (2-b)

Answer 2

Answer:

(2 – b) (3a2 + c2)

Step-by-step explanation:

6a2 – 3a2b – bc2 + 2c2

= 6a2 – 3a2b + 2c2 – bc2 (By grouping)

= 3a2 (2 –b) + c2 (2 – b)

= (2 – b) (3a2 + c2)