Math, asked by gafrul2017, 10 months ago

factorise 6a^3+3a^2-3a

Answers

Answered by sairam2005

0

$6a {}^{3} + 3 {a}^{2} - 3a$

$= 3a(2 {a}^{2} + 3 {a}^{} - 1)$

Answered by aishwaryar1807

5

Answer:

6a³+3a²-3a = 3a(2a²+a-1) = 3a(a+2)(a-1)

Step-by-step explanation:

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