Math, asked by gafrul2017, 1 year ago

factorise 6a^3+3a^2-3a​

Answers

Answered by sairam2005
0

6a {}^{3}  + 3 {a}^{2}  - 3a

 = 3a(2 {a}^{2}  + 3 {a}^{}  - 1)

Answered by aishwaryar1807
5

Answer:

6a³+3a²-3a = 3a(2a²+a-1) = 3a(a+2)(a-1)

Step-by-step explanation:

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